QUANTITATIVE APTITUDE - FOR UPCOMING EXAMINATION

DATA INTERPRETATION

Directions (01-05) : Study the following pie chart and table and answer accordingly.

The following pie-charts show the percentage of employees in two companies X and Y who are working in different units. Total numbers of employees in X and Y are 2500 and 3000 respectively.

The following table shows the ratio of males and females of both the companies in different units

1). In which of the following units, the number of male employees of company X is equal to that of female employees of company Y ?
a) C
b) F
c) A
d) E
e) B

2). By what per cent is the number of female employees of company Y for unit E more than that of male employees of company X for same unit ?
a) 34%
b) 50%
c) 46.66%
d) 54.54%
e) None of these

3). In which of the following two units, the number of male employees for company Y is the same ?
a) A and B
b) A and C
c) D and E
d) B and C
e) None of these

4). Find the ratio of the male employees in unit E of company X to the female employees in unit C of company Y.
a) 2 : 5
b) 3 : 2
c) 2 : 3
d) 1 : 3
e) None of these

5). In how many units of company Y are the female employees more than 200 ?
a) Four
b) Five
c) Six
d) Three
e) None of these

Directions (06–10) : The following line-graph shows the number of males and females of two different towns X and Y during the given years:

6). By what percent (in approx) the average population of both the towns has increased during the period 1994 to 1998 ?
a) 5%
b) 8%
c) 7%
d) 4%
e) None of these

7). Find the ratio between the average number of males of X and Y for the given period.
a) 237 : 230
b) 239 : 230
c) 49 : 48
d) 230 : 237
e) None of these

8). The population of X and Y in 1996 is how many times of 1994 ?
a) 1.05
b) 0.94
c) 1.02
d) 0.91
e) None of these

9). Find the number of years in which the number of females for X and Y are less than their respective average numbers.
a) 0
b) 4
c) 3
d) 5
e) None of these

10). In which of the following year the difference between the number of females in town X and number of males in town Y is maximum?

a) 1994

b) 1995

c) 1998

d) 1996 

e) 1997

Answer with Solution:
1. (A); Number of male employees in unit C for company X
= 14% of 2500 × (3/7) = 150
Number of female employees in unit C for company Y
= 15% of 3000 × (1/3) = 150

2. (E); Number of female employees of company Y in unit E
= 22% of 3000 × 1/3 = 220
Number of male employees of company X in unit E
= 10% of 2500 × 2/5 = 100
:. Required more % = (220-100)/100 × 100
= 120%

3. (B); Number of male employees in different units for company Y : A = 300,
B = 240, C = 300, D = 100, E = 440 and F = 150.
Hence, our answer is A and C.

4. (C); Required ratio = (10%of 2500×2/5) / (15% of 3000×1/3)= 2 : 3

5. (A); Number of female employees for company Y in different units:
A = 60, B = 300, C = 150, D = 500, E = 220 and F = 240

6. (C); Average population (in thousands) of both the towns in 1994
= (45+44+48+45)/2
= 45 + 22 + 24 = 91 and that in 1998
= (50+47+50+47)/ 2
= 50 + 47 = 97
:. Required percentage increase = (6/91) × 100
= 6.59% Approx. 7%.

7. (B); Required ratio

8. (A); Population of X and Y in 1996
= (50 + 47+47 + 48 ) × 1000 = 192000
Population of X and Y in 1994
= (45 + 44 + 48 + 45) × 1000 = 182000
Now, 192 × 1000 = x × 182 × 1000
:. x = (192/182) = 1.05

9. (B); Average number of females for
X =1/5 (45 + 47 + 48 + 50 + 47) × 1000
= 237 × 200 = 47400
Y =1/5 (48 + 49 + 47 + 50 + 50) × 1000
= 244 × 200 = 48800
So, 1994, 1995 and 1998 are the three desired years for X and 1994 and 1996
are the two desired years for Y. Hence the required number of years is four
(1994, 1995, 1996 and 1998).

10. (B)
In 1994 → (45000 – 44000) = 1000
In 1995 → (47000 - 44000) = 3000
In 1996 → (48000 – 47000) = 1000
In 1997 → (50000 – 48000) = 2000

In 1998 → (47000 – 47000) = 0