QUANTITATIVE APTITUDE - FOR UPCOMING EXAMINATION
DATA INTERPRETATION
Direction (Q. 1-5): Total number of candidates applied for SSC exam from six different
cities together is 6.5 lakh. Following pie chart shows the percentage
distribution of total candidates among these cities and the table shows the
percentage of girls applied for SSC from these cities:-
1). What is the total number of boys applied from city B in SSC exam ?
a) 64350
b) 65680
c) 67860
d) 68760
e) 69660
2). What is the difference between total number of boys and total
number of girls applied from city A ?
a) 32400
b) 33800
c) 34200
d) 35500
e) 36300
3). What is the ratio between number of girls applied from city B and
city C ?
a) 3 : 5
b) 4 : 7
c) 5 : 9
d) 7 : 10
e) 8 : 13
4). Number of boys applied from city F is approximately what percent
of total number of candidate applied from all six cities together ?
a) 8.64%
b) 10.92%
c) 11.48%
d) 12.64%
e) 13.5%
5). What is the total number of girls applied from all six cities
together ?
a) 290355
b) 292165
c) 293445
d) 294575
e) 295050
Direction (Q. 6-10): In the given table the percentage of marks scored by five students
in different subjects is shown. Answer following questions based on this table
:-
6). What are the total marks scored by student 'C' in all six
subjects?
a) 421
b) 423.5
c) 425
d) 426.5
e) 429
7). What is the average marks scored in subject 'Q' by all students ?
a) 64.2
b) 66.5
c) 68.4
d) 69.8
e) 71.6
8). Marks scored by student 'C' in subject 'T' is approximately what
percentage of mark scored by student 'D' in subject 'P'?
a) 92.5%
b) 87.5%
c) 82.5%
d) 77.5%
e) 72.5%
9). Marks scored by student 'A' in subject 'U' is approximately how
much percentage more/less than marks scored by student 'B' in subject 'Q' ?
a) 35%
b) 45%
c) 55%
d) 65%
e) 75%
10). What is the aggregate percentage of student 'E' considering all
six subjects ?
a) 47.4%
b) 50.3%
c) 54.5%
d) 57.2%
e) 59%
SOLUTION
Solution:
1).C) Boys = 650000 × (18/100) × (58/100) = 67860
2). B) Diff = 650000 × (20/100) × [(63-37)]/100
= 65×20×26 = 33800
3). D) Ratio =[ 650000 × (18/100) × (42/100)] / [650000 × (24/100) ×
(45/100)]
= (18×42)/(24×45) = 7/10
4). B) FB =
650000× (21/100) × (52/100) = 70980
Req % = (70980/650000) × 100 =
10.92%
5). A) Total Girls
= 650000 /(100 × 100)
× [(20 ×37) + (18 ×42) + (24 ×45)
+ (9 ×51) + (8 ×53) + (21 ×48)]
= 65×
(740+756+1080+459+424+1008) = 65×4467
= 290355
6). D) 150×.65 + 120×.75 + 50×.7 + 50×.54 + 63 + 200×.57
= 97.5 + 90 + 35 + 27 +
63 + 114 = 426.5
7). C) Avg. = [120/(100 × 5)] (65 + 50 +75 + 55+ 40) = (1.2/5) ×285
= 1.2 × 57 = 68.4
8). B) CT =
100× (63/100) = 63, Dp =
150 × (48/100) = 72
9). D) Av =
200×(49.5/ 100) = 99, BQ =
120×(50/100) = 72
Req. % = [(99 – 60)/60] × 100 =
(3900/60) = 65%
10). B) E Total = 150×.56 + 120×.4 + 50×.48 + 50×.46 +
53 + 200×.525
= 84 + 48 + 24 + 23 + 53 + 105
= 337
Total marks = 150 + 120 +50 +50
+ 100 + 200 = 670
Req. % =(337/670) × 100 =
50.298 = 50.3 %
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