QUANTITATIVE APTITUDE - DATA INTERPRETATION 

Direction (Q.1-5): Following line graph shows the percentage profit earned by two companies 'A' and 'B' during the period of 2007 to 2013 :-

1). If the expenditure of company A and B in year 2008 was 18.5 lakh and 17.3 lakh respectively then what was the income of company A and company B together in year 2008 ?

a)    46.46 lakh

b)    47.24 lakh

c)    48.5 lakh

d)    49.38 lakh

e)    50.6 lakh

2). If the income of company A in 2011 and that of B in 2010 are Rs. 24.36 lakh and  Rs. 18.36 lakh respectively then what is the total expenditure of company A in 2011 and company B in 2010. ?

a)    30.4 lakh

b)    31.2 lakh

c)    32.8 lakh

d)    33.5 lakh

e)    34.6 lakh

3). If the expenditure of company A in 2009 and income of company B in 2013 are equal then what will be the ratio of income of company A in 2009 and expenditure of company B in 2013 ?

a)    5 : 4

b)    25 : 16

c)    1 : 1

d)    Can't be calculated

e)    None of these

4). If the expenditure of company A in 2012 and company B in 2009 are equal then the income of company A in 2012 is approximately what percentage of income of company B in 2009 ?

a)    88.9%

b)    96%

c)    112.5%

d)    118.5%

e)    122.5%

5). In the following years in which year the percentage rise/fall percent profit of company B is maximum compare to its previous year ?

a)    2008

b)    2009

c)    2010

d)    2011

e)    2012

Solution:

1). D)  Income A = 18.5× (136/100) = 25.16 lakh,

Income B = 17.3×(140/100) = 24.22 lakh

Total = 49.38 lakh

2). A) Exp. A = 24.36×(100/145) = 16.8 lakh,

Exp. B = 18.36×(100/135) = 13.6 lakh,

Total = 30.40 lakh

3). B)  E _{A - 2009} = I _B-2013 = x (let),

I_A-2009 = x × (125/100)

and _EB-2013 = x× (100/125)

Ratio = (125x/100) × (125/100x) = 25/16

4). C)  Let Exp _A-2012 = Exp _B-2009 = x, I_A-2012 = x× (135/100)

and I _B-2009 = x×(120/100), Req.% = (1.35x/1.2x) ×100 = 112.5%

5). C)  % rise = [(35-20)/20] × 100 = 1500/20 = 75% rise